shiv runs around a square Park of side 135 and Dolly runs around a rectangular Park with length 75 and breadth 40. who cover more distance by how much ?
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Shiv runs around a square park of side 135 cm and Dolly runs around a rectangular park with length 75 cm and breadth 40 cm. Who covers more distance and by how much?
Your answer is that Shiv ran more than Dolly by 290 cm. The explanation is as follows:
Perimeter of square = 4s
Then, perimeter of the square park = 4*135 = 520 m
Perimeter of rectangle = 2 [ L+ b ]
Then, perimeter of the rectangular park =
2 [ 75 +40 ] = 2*115 = 230 cm
Difference between both the final quantities = 520-230 = 290 cm
Because 520 is greater than 230, we can say that Shiv ran more than Dolly by 290 cm.
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Answer:
perimeter of the sq. park =135×4
=540
perimeter of the rect. park =2(75+40)
=230
so Dolly runs more distance by(540-230) 310 *unit*
pls mark this as the brainliest
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