Question

shivam and sanyam together have 25 balls. both lost 4 balls and the product of number of balls they now have is 66 find no. of balls both have initially

Answer 1

let shivam has x balls and sanyam has y balls

then x+y = 25

y=25-x

both lost 4 balls,

then (x-4)*(y-4) = 66

ie, (x-4)*(25-x-4) =66

   (x-4)*(21-x) = 66

21x - x^2 - 84 + 4x =66

x^2-25x +150=0

on solving,x=15 or x=10

therefore one have 10 ball and other has 15