Question

Shivam recharges college in half an hour, when he travels with an certain speed while coming back to home if increases the speed by 20 %. in what time he will reach home?

Answer 1

25 minutes will be required

Steps: -

Let, the initial speed is V1, and time required is t1,

so we know, $V= \frac{Distance}{Time}$

V1= S/T1, and S= V1.T1

Now we have V2 = V1+0.2V1 (given speed is increased by 20%)

therefore V2 = 1.2V1

and V2= S/T2 (Because distance won't change)

Now putting values 1.2V1= V1.T1/T2

And putting T1 = 30 minutes we get the answer=25 minutes