Math, asked by abhishek147, 1 year ago

shobhit is three years older than pankaj six years ago shobhit's age was four times pankaj's age find their present ages


abhishek147: please answer this
abhishek147: i am Abhishek

Answers

Answered by frank55oops
3
Please use comma in the question for better understanding.
From what I understood:
Present :   Shobit = Pankaj + 3                ......(1)
6 Years ago :   (Shobit - 6) = 4*(Pankaj - 6)       .....(2)

From 1 and 2,
Pankaj = 7, Shobit = 10 years at present

abhishek147: please do this step by step
abhishek147: you are donkey
Answered by mysticd
4
Hi ,

At present
________

pankaj age = x years

shobhit age = (3+ x )years

six years ago
__________

pankaj age = ( x - 6 ) years

shobhit's age = ( 3 + x - 6 )=( x - 3 ) years

according to the problem given,

shobhit's age = 4 ×pankaj's age

x - 3 = 4(x - 6)

x - 3 = 4x - 24

x - 4x = -24 + 3

-3x = - 21

x = (-21 )/ ( -3 )

x = 7

Therefore,

at present ,

pankaj age = x = 7 years

shobhit's age = 3 + x

= 3 + 7

= 10 years

I hope this helps you.

:)

abhishek147: very thanks to you
mysticd: :)
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