Shobo's mother's present age is six times Shobo's present age. Shobo's age five years from now will be one third of his mother's present age. What are their present ages?
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Answer:
Question:-
Shobo's mother's present age is six times Shobo's present age. Shobo's age five years from now will be one third of his mother's present age. What are their present ages?
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Given :-
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- Shobo's mother's present age is 6 times Shobo's present age.
- Shobo's age 5 years from now will be 1/3 of his mother's present age.
To find :-
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- Their present ages.
Solution :-
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- Consider,
Present age of Shobo's Mother= x years
Present age of Shobo's = y years
According to the 1st condition :-
Shobo's mother's present age is 6 times Shobo's present age.
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According to the 2nd condition :-
Shobo's age 5 years from now will be 1/3 of his mother's present age.
Present age of Shobo = 5 years
Now , put y = 5 in eq(1) for getting the value of x.
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Present age of Shobo's Mother = 30 years.
Therefore , the present age of Shobo is 5 years & present age of Shobo's Mother is 30 years.
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Let the present age of Shobo be x years .
Then, Shobo's mother's age =6x years
After 5 years: Shobo's age =(x+5) years
∴(x+5)=×(6x)
On cross multiplying, we get
⇒3×(x+5)=6x
⇒3x+15=6x
⇒3x−6x=−15
⇒3x=−15
Taking 3 to RHS
⇒x=
Given that shobo's Mother present age is 6 times Shobo's present age
∴5×6=
Therefore, present age of Shobo is 5 years and his mother is 30 years.