Math, asked by krushnakantpatil679, 11 months ago

shobo 's mothers present age is six times shobos present age .shobo's age five years from now will be one third of his mothers present age .what are thier present ages


krushnakantpatil679: what is your name
Anonymous: why?
krushnakantpatil679: please provide answer detailed like solving sum
Anonymous: is the answer right
krushnakantpatil679: i don't know

Answers

Answered by Anonymous
43
let the present age of shobo be x

so, the present age of her mother will be 6x

age of shobo after 5 years = 5+x

A/q. 5+x = 6x/3
=> 5 + x = 2x
=> x = 5

so ,the present age of shobo = x = 5 years
" " " mother = 6x = 6*5 = 30 years

Anonymous: nice answer
Anonymous: thnx
raj70324: nic
Anonymous: it is also fine...
Answered by Anonymous
62
<b><u><i>Let shobo's present age = x years

His mother's present age = 6x years

After five years :

Add 5 to shobo's age => x + 5

Shobo's age will be one third of his mother's age -

The equation becomes :

 = > \frac{1}{3} \times 6x = x + 5 \\ \\ = > \frac{6x}{3} = x + 5 \\ \\ = > 2x = x + 5 \\ \\ = > 2x - x = 5 \\ \\ = >1 x = 5 \\ \\ = > x = 5
Hence,

Shobo's present age = x = 5 years

His mother's present age = 6x = 6 × 5 = 30 years

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rubku: gr8 answer
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