Question

show covalent bond formation in metane​

Answer 1

Answer:

$[tex] { {3}^{2} }^{3}  \times  {(2 \times  {3}^{5}) }^{ - 2}  \times  {18}^{2 }  \\  \\  =  {3}^{6}  \times  \frac{1}{4 \times  {3}^{10} }  \times  {18}^{2}  \\  \\  =  \frac{ {18}^{2} }{4 \times  {3}^{4} }  \\  \\  =  \frac{ \cancel{18 } \: ^{ \cancel{6}} \: ^{ \cancel{2}}\times { \cancel{18}}  \: ^{ \cancel{6 }} \:  ^{ \cancel{2}} \:  ^1 }{ { \cancel{4 }\:_1}\times { \cancel{3} \: _1} \times { \cancel{3 } \: _1}\times { \cancel{3} \:_1} \times { \cancel{3} \: _1} }  \\  \\  = { \huge{ \red{ \boxed{1}}}}$[/tex]

Answer 2

Answer:

Debraj P. Methane (CH4 ) is a covalent compound containing covalent bonds. Therefore, one atom of carbon shares its four electrons with four atoms of hydrogen to form four covalent bonds.

Explanation:

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