Show dat 1) 1-sin 60` / cos 60 = tan 60 -1 / tan 60 +1
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Answered by
322
1-sin60°/cos60°
=(1-√3/2)/(1/2)
=(2-√3)/2×2/1
=2-√3
tan60°-1/tan60°+1
=(√3-1)/(√3+1)
=(√3-1)(√3-1)/(√3+1)(√3-1)
=(3-2√3+1)/(3-1)
=(4-2√3)/2
=2(2-√3)/2
=2-√3
∴, LHS=RHS(Proved)
=(1-√3/2)/(1/2)
=(2-√3)/2×2/1
=2-√3
tan60°-1/tan60°+1
=(√3-1)/(√3+1)
=(√3-1)(√3-1)/(√3+1)(√3-1)
=(3-2√3+1)/(3-1)
=(4-2√3)/2
=2(2-√3)/2
=2-√3
∴, LHS=RHS(Proved)
Answered by
26
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