Show how butanoic acid may be converted to each of the following compounds:
(a) 1-Butanol
(b) Butanal
(c) 1-Chlorobutane
(d) Butanoyl chloride
(e) Phenyl propyl ketone
(f) 4-Octanone
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Answer:
(a) CH3CH2CH2COOH+ LiAlH4
= 1- butanol
(b) CH3CH2CH2COOH +SOCl2
= CH3CH2CH2COCl + H2(Pd/BaSO4)
= Butanal
(c)
CH3CH2CH2COOH+ LiAlH4
= 1- butanol+ PCl5 = 1-chlorobutane
(d) CH3CH2CH2COOH +SOCl2
= CH3CH2CH2COCl
(e)
CH3CH2CH2COOH +SOCl2
= CH3CH2CH2COCl + (C6H5)2Cd =
= C6H5COCH2CH2CH3
(f)
CH3CH2CH2COOH +SOCl2
= CH3CH2CH2COCl + (C4H9)2Cd =
= CH3CH2CH2COCH2CH2CH2CH3
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