show how the difference between a 5 digit number and the number formed by reversing the order of its digit is divisible by 9.
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Lets xy is a two digit number.
From the question, we have to check for xy−yx
xy−yx=(10x+y)−(10y+x)=9x−9y=9(x+y)
Which is always divisible by 9.
Hence the difference of a two digit number and the number obtained by reversing the digit is always divisible by 9.
❥︎hope it helps u mate.........
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Answer:
10008 is the correct answer
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