Show how would you connect three resistors of 6 ohm each so that the equivalent resistance of combination is
a) 9 ohm
b)6 ohm
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R1, R2, R3 each of 6 Ω
a) Equivalent resistance of 9 Ω
9 - 6 = 3 ohms...
3 = 6 / 2....
so R1 + R2 R3 / (R2 + R3) = 9 Ω
we connect R3 and R2 in parallel. Then we connect R1 in series with them.
b) we use one of the resistances only to get 6 Ω. We cannot make a series or parallel combination of 3 resistances to get 6 Ω again.
a) Equivalent resistance of 9 Ω
9 - 6 = 3 ohms...
3 = 6 / 2....
so R1 + R2 R3 / (R2 + R3) = 9 Ω
we connect R3 and R2 in parallel. Then we connect R1 in series with them.
b) we use one of the resistances only to get 6 Ω. We cannot make a series or parallel combination of 3 resistances to get 6 Ω again.
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