Physics, asked by LaherParmer599, 1 year ago

The maximum heigth for a projectile is ?

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Answered by MASelvam

max h=(v₀)²sin²(q) /2 g

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Answered by kvnmurty

u = initial velocity of the projectile
θ = angle of projection with the horizontal
H = maximum height above the horizon that the projectile attains
   = u² Sin²θ / (2 g)

derivation:
   initial velocity in vertical direction = u sinθ
   v² = u² - 2 g H
   v = 0 when the projectile reaches the top.
distance travelled H = u² Sin² θ / 2 g

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