show how would you join 3 resisters , each of 9ohm so that the equivalent resistance of the combination is i)13.5ohm ii)6ohm
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1.join two resistor in parallel and third in series
So 1/9+1/9 = 4.5
4.5 + 9 = 13.5
2.join 2 resistor in series and third in parallel
R+R =9 + 9 = 18
1/R + 1/R=1/18 + 1/9 = 1/6
R= 6
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So 1/9+1/9 = 4.5
4.5 + 9 = 13.5
2.join 2 resistor in series and third in parallel
R+R =9 + 9 = 18
1/R + 1/R=1/18 + 1/9 = 1/6
R= 6
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