show m^4+4 where n is greater than 1 is a composite numbers
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Answer:
n 4+4=(n 4 +4n 2+4)−4n 2
=(n 2+2) 2−(2n) 2
=(n 2+2+2n)(n 2+2−2n)
This clearly shows that n
4+4 is a composite number
Step-by-step explanation:
i have written n instead of m
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