Question

show Shridharacharya's rule​

Answer 1

Answer:

1. x=(-b+√(b^2–4ac))/2a

2. x=(-b-√(b^2–4ac))/2a

Step-by-step explanation:

Sridharacharya rule is a rule used to find roots of a quadratic equation.

For any quadratic equation ax^2+bx+c=0

there exists two values of x

The respective values are:

1. x=(-b+√(b^2–4ac))/2a

2. x=(-b-√(b^2–4ac))/2a