Question

show
$x ^{2} + 4x + 5 has no \: zero$
so that X square + 4 x + 5 has no zero

Answer 1

D = b ^ 2 - 4 ac

= 16 - 4 * 5

= 16 - 20 = -4

which is negative

Answer 2

Answer:

x² + 4x + 5

Discriminant = b² - 4ac

= 4² - 4 ( 1 × 5 )

= 16 - 20

= -4

Proved

Thanks!