show tha isosceles triangles, angles opposite to equal side are equal
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Given: ABC isosceles triangle
i.e. AB=AB
To prove: angleB=angleC
Construction: Draw a bisector of angle A intersecting BC at D.
Proof: In triangle BAD & triangle CAD
AB=AC {Given}
angle BAD= angle CAD {By Construction}
AD=AD {common}
therefore, triangle BAD is congruent to triangle CAD {SAS rule}
Thus,
angle ABD=angle ACD {CPCT}
==> angle B= angle C
Hence proved.
Hope it helps u.
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