Show that 0.3333 = 0.3bar only on 3 can be expressed in the form p/q where p q are integers and q not equal to zero
Answers
Answered by
3
Heya !!!
Let X = 0.3 ( bar on 3 )
Then, X = 0.33 ----(1)
Multiply equation (1) by 10 we get,
10X = 3. 33 ------(2)
Subtract equation (1) from equation (2) we get,
10X = 3 . 33
X = 0.33
----------------
9X = 3 [ Bar cancelled ]
X = 3/9 = 1/3 [ P/Q form ]
★ HOPE IT WILL HELP YOU ★
Let X = 0.3 ( bar on 3 )
Then, X = 0.33 ----(1)
Multiply equation (1) by 10 we get,
10X = 3. 33 ------(2)
Subtract equation (1) from equation (2) we get,
10X = 3 . 33
X = 0.33
----------------
9X = 3 [ Bar cancelled ]
X = 3/9 = 1/3 [ P/Q form ]
★ HOPE IT WILL HELP YOU ★
VijayaLaxmiMehra1:
:-)
Answered by
2
Hey!!!
Let x = 0.3 ( bar on 3 )
Then x = 0. 3333------(1)
Multiplying eq'n (1) by 10
10x = 3.3333------(2)
Subtracting eq'n (1) from (2)
10x = 3.3333
x = 0.3333
------------------
9x = 3
=> x = 3 / 9
=> x = 1 / 3
Hope it will helps you ✌
Let x = 0.3 ( bar on 3 )
Then x = 0. 3333------(1)
Multiplying eq'n (1) by 10
10x = 3.3333------(2)
Subtracting eq'n (1) from (2)
10x = 3.3333
x = 0.3333
------------------
9x = 3
=> x = 3 / 9
=> x = 1 / 3
Hope it will helps you ✌
Similar questions