Show that "1-2sin theta cos theta>=0" for all "theta in R
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Answered by
31
Answer:
1 - 2SinθCosθ ≥ 0
Step-by-step explanation:
Show that "1-2sin theta cos theta>=0"
We need to show that
1 - 2SinθCosθ ≥ 0
As we know that Sin2θ = 2SinθCosθ
if 1 - Sin2θ ≥ 0
if -Sin2θ ≥ - 1
if Sin2θ ≤ 1
Which is true
other way
1 - 2SinθCosθ
as we know that Cos²θ + Sin²θ = 1
= Cos²θ + Sin²θ - 2SinθCosθ
= (Cosθ - Sinθ)²
and square of any number ≥ 0
=> (Cosθ - Sinθ)² ≥ 0
=> 1 - 2SinθCosθ ≥ 0
Answered by
6
Answer:
the answer is theta lies between 0 to 2
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