show that (
1, 3), (3, -1), (-5, -5) form a right angled
triangle.
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Distance Formula
→ √[(x₂ - x₁)² + (y₂ - y₁)²]
Solution
AB → √[(3 - 1)² + (- 1 - 3)²] = √20
BC → √[(3 + 5)² + (- 1 + 5)²] = √80
CA → √[(1 + 5)² + (3 + 5)²] = 10
What a right (∆) have?
→ H² = B² + P²
→ 10² = √80² + √20²
→ 100 = 80 + 20
→ 100 = 100
→ L.H.S = R.H.S
Yes, these coordinates form right traingle (∆).
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