Question

Show that

1/(3-√8) - 1/(√8-√7) + 1/(√7-√6) - 1/(√6-√5) + 1/(√5-2) = 5

Guys please answer fast...​

Answer 1

Step-by-step explanation:

Rationalising factor of 3-√8 is 3+√8

Rationalising factor of√8-√7 is √8+√7

and so on

1/(3-√8)×3+√8/3+√8=3+√8

1/√8-√7=√8+√7 and so on

1/(3-√8)-1/√8-√7)+1/(√7-√6)-1/√6-√5)+1/√5-2)

=3+√8-√8-√7+√7+√6-√6-√5+√5+2

=3+2

=5

Answer 2

Answer:

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Step-by-step explanation:

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