Question

Show that (-1+√3i)³ is real number

Answer 1

Answer:

8

Step-by-step explanation:

(✓3i)^3-3(✓3i)^2(1)+3(✓3i)(1)^2-(1)^3

=-✓3i+9+✓3i-1

=9-1

=8

Answer 2

Step-by-step explanation:

multiply divide by 8

8[(-1/2+i√3/2)^3]

8[(cos120°+isin120°)^3]

8[e^(i2π/3*3)]

8[e^(i2π)]

8[cos2π+isin2π]

8

or directly -1/2+i√3/2=w(omega)

from 1 step

8(w^3)

8

hence proved

hope it helps u