Question

show that (1, 4), (3, -2), and(-3, 16) are co- linear​

Answer 1

Answer:

p1 , p2 and p3 are collinear.

Step-by-step explanation:

If slope of p1(1,4) and p2(3,-2) is equal to slope of p2(3,-2) and p3(-3,16)

slope1 = (-2-4)/3-1 = -3

slope2 = 16-(-2)/ (-3)-(3) = -3

Hence, p1 , p2 and p3 are collinear.

Answer 2

Answer:

Step-by-step explanation:

x₁(y₂ - y₃) + x₂(y₃ - y₁) + x₃(y₁ - y₂) = 0

1(-2 - 16) + 3(16 - 4) +(-3)(4 -(-2))

1(-2 - 16) + 3(16 - 4) -3(4 +2)

-18 + (3)12 - 3(6)

-18 + 36 - 18

-36 + 36

0

Hence, points (1, 4), (3, -2), and (-3, 16) are colinear.