Question

Show that
1/cos-cos ø =
tanø.sinø​

Answer 1

In RHS,

TanØ × sinØ

sinø/cosø × sinø (tanø = sinø/cosø)

sin²ø/cosø

1-cos²ø/cosø. (sin²ø + cos²ø = 1)

In LHS,

1/cosø - cosø

1 - cos²ø/cosø

Thus, LHS=RHS. (proved)