Show that -1 < tanhx < 1 for all x
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See....
We know Tan 45=1
When The Value of x is below45 the Value Goes within Decimal Values....
But it never Reaches Zero(Though Its Not absolute... But it dosent Goes beyond 0.
And When x increases above 45 The Value again goes Decimal... √3,... So...
Either way Its Decimal And The Highest no: is 1.
Now Let h be any Value.
so....
Tanhx will be greater than -1 and Less than 0 For When h is negative...(in certain cases atleast)
and Tanxh will be greater than 0 and less than 1 when h is positive.
so -1<tan(hx)<+1
We know Tan 45=1
When The Value of x is below45 the Value Goes within Decimal Values....
But it never Reaches Zero(Though Its Not absolute... But it dosent Goes beyond 0.
And When x increases above 45 The Value again goes Decimal... √3,... So...
Either way Its Decimal And The Highest no: is 1.
Now Let h be any Value.
so....
Tanhx will be greater than -1 and Less than 0 For When h is negative...(in certain cases atleast)
and Tanxh will be greater than 0 and less than 1 when h is positive.
so -1<tan(hx)<+1
Leukonov:
Hope it Helps...
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