Question

show that 1/p1+1/p2-1/p3=2abcos2c/2/delta (a+b+c)​

Answer 1

Answer:

solve by this

Step-by-step explanation:

Since p

1

,p

2

,p

3

are perpendiculars from the vertices A, B, C to the opposite sides, we have

△=

2

1

ap

1

=

2

1

bp

2

=

2

1

cP

3

Hence

p

1

1

+

p

2

1

p

3

1

=

2△

a

+

2△

b

−

2△

c

=

2△

a+b−c

=

2△

a+b+c−2c

=

2△

2s−2c

=

△

s−c

=

△s

ab

.

ab

s(s−c)

=

△s

ab

cos

2

2

1

C=

2

1

C=

(a+b+c)△

2ab

cos

2

2

1

C.

Answer 2

Answer:

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Step-by-step explanation:

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