Question

. Show that :-
1-sin 60°
.=2-√3.
cos 60°​

Answer 1

$1 - sin60 = 1 - \sqrt{3 } \div 2 \\ = 2 - \sqrt{3} \div 2 = 2 - \sqrt{3} \times 1 \div 2 \\ = 2 - \sqrt{3} cos60$

LHS=RHS

hence proved

Answer 2

Answer:

From LHS:

1-Sin60°

1-√3/2

(2-√3)1/2

2-√3.cos 60° (because 1/2= cos 60°)