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1-sin60°÷cos60°=tan 60°-1÷ tan60+1
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L.H.S:- 1-sin60/cos60
=1-√3/2÷1/2
=1-√3
RHS:- tan60-1÷tan60+1
=√3-1÷√3+1
multiply conjugate we get both up and down we get =(3-1+2√3)÷(3-1)=√3+1
but the qus is error
=1-√3/2÷1/2
=1-√3
RHS:- tan60-1÷tan60+1
=√3-1÷√3+1
multiply conjugate we get both up and down we get =(3-1+2√3)÷(3-1)=√3+1
but the qus is error
gauravkhatri474:
You did wrong bro
where
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Here 1st we need to solve LHS then RHS both will come equal... hence proved
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ye this process is correct
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