Math, asked by jayababu4998, 8 months ago

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[1+tan^2A/1+cot^2A]=
[1+tan^2A/1+cotA]^2=tan^2A

Answers

Answered by todinson255

2

Answer:

Step-by-step explanation:

=1+tan^2a/1+cot^2a

=sec^2a/cosec^2a

=1/cos^2a/1/sin^2a

=tan^2a

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