show that (1+tan20) ( 1+tan25) = 2 .
[use tan(A+B) = tan A+tan B
1-tanA+tanB ]
srlkhu:
the Q. isn't ri8 the Q is ( 1+ tan 25) = 2 .[ use tan(A+B) = tanA+tanB/ 1- tanAtanB
any ways okay! cool!
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1+ tan25 + tan20 + tan20tan25 +1 - 1
2 + tan(25 + 20)(1 - tan20tan25) - (1 - tan20tan25) { using the formula you gave ie use tan(A+B) = tanA+tanB/ 1- tanAtanB}
2 + (1 - tan20tan25)(tan45 - 1)
2 + (1 - tan20tan25)(1 - 1)
2 + 0
= 2 PROVED
2 + tan(25 + 20)(1 - tan20tan25) - (1 - tan20tan25) { using the formula you gave ie use tan(A+B) = tanA+tanB/ 1- tanAtanB}
2 + (1 - tan20tan25)(tan45 - 1)
2 + (1 - tan20tan25)(1 - 1)
2 + 0
= 2 PROVED
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