Show that 12^n can't end with the digit 0 or 5 for any natural Number n.
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Answered by
7
since factors of 12 are 2 ×6 . it includes 2 but not 5 .so 12^n cant end with digit 0 or 5
Answered by
14
Hii friend,
Solution:- 12^n = (2² + 3)^n
=> 2^2n × 3^n .
Therefore, prime factorisation of 12^n does not contain 5 as a factor.
Hence,
12^n can never end with the digit 0 or 5 for any natural number n.
HOPE IT WILL HELP YOU.... :-)
Solution:- 12^n = (2² + 3)^n
=> 2^2n × 3^n .
Therefore, prime factorisation of 12^n does not contain 5 as a factor.
Hence,
12^n can never end with the digit 0 or 5 for any natural number n.
HOPE IT WILL HELP YOU.... :-)
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