Question

show that 12n can not end with digit 0 or 5
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Answer 1

Number = $12^{n}$

$</p><p></p><p></p><p>\rightarrow \quad 12^{n} \\</p><p></p><p>\rightarrow \quad (2 \times 3 \times 2 )^{n} \\ </p><p></p><p>$

Since the number doesn't contain 5 or 10 as factor so this number can not end with digit 0 and 5.

Answer 2

Answer:

Step-by-step explanation:

Here is the answer