Show that 12n cannot end with the digits 0 and 5 for any natural number n
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Hey friend ✋! here is your answer
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✅ To end with the digit 0 the factor must be in (2×5)^n form but here
✔️12n cam be written as (2×6)^n.
✅(2×6)^n this is not in the form of (2×5)^n & here 5 is not the factor 12.
So, therefore 12n cannot end with the digit 0 for any natural number n.
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⭐️Hope it helps you ⭐️
____________________________
✅ To end with the digit 0 the factor must be in (2×5)^n form but here
✔️12n cam be written as (2×6)^n.
✅(2×6)^n this is not in the form of (2×5)^n & here 5 is not the factor 12.
So, therefore 12n cannot end with the digit 0 for any natural number n.
________________________
⭐️Hope it helps you ⭐️
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