Question

the identical containers hold Methane Oxygen and SO2 gas in the mass ratio of 4:2:1 respectively but at the same temperature the pressure exerted by ch4 :O2 : SO2 are in the ratio of?

Answer 1

$\text{Use Ideal Gas equation}\\pV=nRT\\\Rightarrow p \propto n\\\Rightarrow {p}_{{CH}_{4}}:{p}_{{O}_{2}}:{p}_{{SO}_{2}}\\={n}_{{CH}_{4}}:{n}_{{O}_{2}}:{n}_{{SO}_{2}}\\=\frac{{\text{Mass}}_{{CH}_{4}}}{{\text{Molar Mass}}_{{CH}_{4}}}:\frac{{\text{Mass}}_{{O}_{2}}}{{\text{Molar Mass}}_{{O}_{2}}}:\frac{{\text{Mass}}_{{SO}_{2}}}{{\text{Molar Mass}}_{{SO}_{2}}}\\=\frac{4}{16}:\frac{2}{32}:\frac{1}{64}\\=16:4:1$