show that 192 is not a perfect cube
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Answer:
Grouping the prime factors of 192 into triples, 3 is left over. ∴ 192 is not a perfect cube. i.e. 64 is a perfect cube. Thus, the required smallest number is 3.
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Answer:
192= 2×2×2×2×2×2×3
Here 3 does not occur in a group of there hence 192 not a perfect cube
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