show that 2√3-1 is irrational no.
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Answered by
1
Hello friend
Here goes your answer
Let us assume 2√3-1 to be a rational number
A rational number is a one which can be expressed in the form p/q
So 2√3-1=p/q
For some integers p,q
2√3=(p/q)+1
2√3=2q+p/q
√3=2q-p/2q
As p,q are integers the RHS will be a rational number
So LHS also needs.to be a rational number
But this contradicts the fact that√3 is irrational. This contradiction has arisen due to our false assumption.
Therefore 2√3-1is irrational
Here goes your answer
Let us assume 2√3-1 to be a rational number
A rational number is a one which can be expressed in the form p/q
So 2√3-1=p/q
For some integers p,q
2√3=(p/q)+1
2√3=2q+p/q
√3=2q-p/2q
As p,q are integers the RHS will be a rational number
So LHS also needs.to be a rational number
But this contradicts the fact that√3 is irrational. This contradiction has arisen due to our false assumption.
Therefore 2√3-1is irrational
yashpatidar:
thankyou yarrr
Answered by
0
Hey there !!
Lets assume that 2√3-1 is rational .
Let ,
2√3 - 1 = r , where "r" is rational .
2√3 = r +1
√3 = r +1 /2
here ,
its very clear that , RHS is purely rational.
But on the other hand , LHS is irrational.
This is a contradiction.
Hence ,
our assumption was wrong.
therefore ,
2√3-1 is irrational
Lets assume that 2√3-1 is rational .
Let ,
2√3 - 1 = r , where "r" is rational .
2√3 = r +1
√3 = r +1 /2
here ,
its very clear that , RHS is purely rational.
But on the other hand , LHS is irrational.
This is a contradiction.
Hence ,
our assumption was wrong.
therefore ,
2√3-1 is irrational
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