Show that 2√3 is irrational.
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Rational numbers can be written in the form pq where p and q are integers and q≠0.
Now, given number is ,
23–√=23–√∗3–√3–√=63–√
So, it is in pq form and q≠0.
But, as q is not an integer,
given number is not a rational number.
Hence, 23–√ is an irrational number.
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