Show that 2 and -1/3 are the zeroes of the polynomial 3x^3-2x^2-7x-2. Also, find the third zero of the polynomial.
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To show that these are roots of that polynomial
then first we put these values of x
first,we put 2
3(2)^3-2(2)^2-7(2)-2
24-8-14-2
=24-8-16
=24-24=0
2 is zero of the polynomial
now we put -1/3
3(-1/3)^3-2(-1/3)^2-7(-1/3)-2
3(-1/27)-2/3+7/3-2
-1/9-2/3+7/3-2=0
then first we put these values of x
first,we put 2
3(2)^3-2(2)^2-7(2)-2
24-8-14-2
=24-8-16
=24-24=0
2 is zero of the polynomial
now we put -1/3
3(-1/3)^3-2(-1/3)^2-7(-1/3)-2
3(-1/27)-2/3+7/3-2
-1/9-2/3+7/3-2=0
ManitKadian:
Can you also explain how to find third zero of the polynomial
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