Question

show that -2 is zero of 4x^3-5x^2-23x+6​

Answer 1

Answer:

I think question answer was 1

Answer 2

Answer:

Step-by-step explanation:

4$x^{3}$-5$x^{2}$-23$x$+6

put $x=-2$ then,

$4*(-2)^{3} -5*(-2)^{2} -23*(-2)+6\\4*(-8)-5*4-23*(-2)+6\\-32-20+46+6\\\\= 0$

i am not sure if this is correct or not!