Trigonometry:-
prove
(1+cos theta) (1-cos theta) (1+cot² theta) =1
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Proof:-
(1+cos theta) (1-cos theta) (1+cot² theta) =1
LHS
(1+cos theta) (1-cos theta) (1+cot² theta) [(a+b)(a-b=a^2-b^2)]
=(1-cos^2theta)(1+cot² theta) [identity used:- sin^2theta+cos^2theta=1]
=(sin^2theta)(1+cot² theta) [identity used :- 1+cot^2theta=cosec^2theta]
=(sin^2theta)(cosec^2theta)
=sin^2theta x 1/sin^2theta
=1
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