show that 21^n can not end with digits 0,2,4,6,8for any naturL number ' n'
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if 21 n ends with 0,2,4,6&8 it would have 2 as it's factor but factors of 21 are 3 and 7.
hence, 21n cannot end with the digit 0,2,4,6and 8for any natural number n
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