Show that: (2a²+b²) – (2a-b²)/ab = 8
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Answer:
2(a^2 + b^2 ) = (a + b)^2
2a^2 + 2b^2 = a^2 + b^2+ 2ab
a^2 + b^2 = 2ab
a^2 - 2ab + b^2 = 0
(a-b)^2 = 0
a-b = 0
a= b
Step-by-step explanation:
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