Question

show that 2sin48 x 3sec42=6

Answer 1

LHS--> 2sin48×3sec42=2sin48×3×1/cos42

(sec=1/cos)=2sin48×3×1/sin(90-42) [cos=sin(90-theta)]

=2×sin48×3×1/sin48

=2×3 (because sin 48 will getcancelled)

=6

=RHS