Question

Show that 2x^2+5x-58=0​

Answer 1

Answer:

There are two real solution we have got in this equation

x =(-5+√489)/4= 4.278 or

x =(-5-√489)/4=-6.778

Step-by-step explanation:

According to the Quadratic Formula, x , the solution for Ax2+Bx+C = 0 , where A, B and C are numbers, often called coefficients, is given by :

- B ± √ B2-4AC

x = ————————

2A

In our case, A = 2

B = 5

C = -58

Accordingly, B2 - 4AC =

25 - (-464) =

489

Applying the quadratic formula :

-5 ± √ 489

x = ——————

4

√ 489 , rounded to 4 decimal digits, is 22.1133

So now we are looking at:

x = ( -5 ± 22.113 ) / 4

Two real solutions:

x =(-5+√489)/4= 4.278

or:

x =(-5-√489)/4=-6.778