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(2x+5)²-20x=(2x-5)²
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Answered by
14
hii friend
LHS=(2x+5)^2 - 20x
=(2x)^2+2×2x×5+5^2 - 20
x =4x^2+25+20x - 20x
LHS=4x^2+25
RHS=(2x-5)^2
=(2x)^2 - 2×2x×5+5^2
=4x^2+25-20x
so LHS not equal to RHS
hope it helps you
thank you
if any mistake report it
LHS=(2x+5)^2 - 20x
=(2x)^2+2×2x×5+5^2 - 20
x =4x^2+25+20x - 20x
LHS=4x^2+25
RHS=(2x-5)^2
=(2x)^2 - 2×2x×5+5^2
=4x^2+25-20x
so LHS not equal to RHS
hope it helps you
thank you
if any mistake report it
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Answered by
5
here is your answer dear
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plz mark as brainliest answer
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