Show that
(2x+5)²-20x=(2x-5)²
Answers
Answered by
14
hii friend
LHS=(2x+5)^2 - 20x
=(2x)^2+2×2x×5+5^2 - 20
x =4x^2+25+20x - 20x
LHS=4x^2+25
RHS=(2x-5)^2
=(2x)^2 - 2×2x×5+5^2
=4x^2+25-20x
so LHS not equal to RHS
hope it helps you
thank you
if any mistake report it
LHS=(2x+5)^2 - 20x
=(2x)^2+2×2x×5+5^2 - 20
x =4x^2+25+20x - 20x
LHS=4x^2+25
RHS=(2x-5)^2
=(2x)^2 - 2×2x×5+5^2
=4x^2+25-20x
so LHS not equal to RHS
hope it helps you
thank you
if any mistake report it
loveme111:
is i am handsome yes or no
tanvi
ok
bye
Answered by
5
here is your answer dear
plz mark as brainliest answer
plz mark as brainliest answer
Attachments:
Similar questions