show that (√3/2+i/2)^3=i
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Step-by-step explanation:
(√3/2 +i/2)3=i
3√3/2 +3i/2=i
2×3√3/2+2×3i/2=2i
3√3+3i=2i
3i-2i=(-3√3)
i=(-3√3)
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