Question

show that 3√2 is irrational​

Answer 1

Step-by-step explanation:

Prove :

Let 3+√2 is an rational number.. such that

3+√2 = a/b ,where a and b are integers and b is not equal to zero ..

therefore,

3 + √2 = a/b

√2 = a/b -3

√2 = (3b-a) /b

therefore, √2 = (3b - a)/b is rational as a, b and 3 are integers..

It means that √2 is rational....

But this contradicts the fact that √2 is irrational..

So, it concludes that 3+√2 is irrational..

hence proved..

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Answer 2

Answer:

root 2 is a irrational no. and if we multiply any rational no. with irrational no. then product is also irrational. so 3 root 2 is irrational no.