show that 3+√2 is irrational number.
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Answered by
2
Answer:
let is assume that 3+√2 is rational
let,3+√2=a/b(where a and b are co primes thus they have a common HCF=1)
ATQ,√2=a/b-3
we know that √2 is irrational
so, a/b-3 will also be irrational(because lf one side is irrational then another will also be irrational)
so, our supposition is wrong
3+√2 is irrational
anirudh00:
plz make it brillianist
Answered by
2
Answer:
Prove :
Let 3+√2 is an rational number.. such that
3+√2 = a/b ,where a and b are integers and b is not equal to zero ..
therefore,
3 + √2 = a/b
√2 = a/b -3
√2 = (3b-a) /b
therefore, √2 = (3b - a)/b is rational as a, b and 3 are integers..
It means that √2 is rational....
But this contradicts the fact that √2 is irrational..
So, it concludes that 3+√2 is irrational..
hence proved..
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