Question

Show that 3√3+√5 is an irrational

Answer 1

Answer:

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Step-by-step explanation:

Let us assume that 3 + √5 is a rational number. Here, {(a - 3b) ÷ b} is a rational number. ... → a and b both are co-prime numbers and 5 divide both of them. So, √5 is a irrational number.

Answer 2

$\huge\underline\mathbb{Question!!}$

Show that 3√3+√5 is an irrational

Let us assume that 3 + √5 is a rational number. Here, {(a - 3b) ÷ b} is a rational number. ...

→ a and b both are co-prime numbers and 5 divide both of them. So, √5 is a irrational number.

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