Show that √3 is an is
irrational number
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Step-by-step explanation:
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anshkumar8257:
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Answer:
given
√3 is an irrational number
let √3 is a rational number
√3=p|q ( q not equal to 0) (p,q) = 1
squring on both sides
(√3)x = (p|q)2
3=p2 | q2
3q2 =p2 =1
p2 is mulpitiple of = 3 = p is also multiple of 3
let p= 3k
put p= 3k in equation (1)
3q2 = [3k ]2
3q2 = 9k2
q2 = 9k2
3
q2 = 3k2
q2 is multiple of 3 = q is also multiple of 3
the height common factor = 3
this is a contradiction our assumption is false
√3 is an irrational
I hope it helps for you..
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